5(t+2)=3(t-1)

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Solution for 5(t+2)=3(t-1) equation: 



5(t+2)=3(t-1)

We move all terms to the left:

5(t+2)-(3(t-1))=0

We multiply parentheses

5t-(3(t-1))+10=0



We calculate terms in parentheses: -(3(t-1)), so:

3(t-1)

We multiply parentheses

3t-3

Back to the equation:

-(3t-3)



We get rid of parentheses

5t-3t+3+10=0

We add all the numbers together, and all the variables

2t+13=0

We move all terms containing t to the left, all other terms to the right

2t=-13

t=-13/2

t=-6+1/2

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