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X(3X-22)=80
We move all terms to the left:
X(3X-22)-(80)=0
We multiply parentheses
3X^2-22X-80=0
a = 3; b = -22; c = -80;
Δ = b2-4ac
Δ = -222-4·3·(-80)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-38}{2*3}=\frac{-16}{6} =-2+2/3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+38}{2*3}=\frac{60}{6} =10 $
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