3(5y-2)=7(3y+5)

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Solution for 3(5y-2)=7(3y+5) equation:



3(5y-2)=7(3y+5)
We move all terms to the left:
3(5y-2)-(7(3y+5))=0
We multiply parentheses
15y-(7(3y+5))-6=0
We calculate terms in parentheses: -(7(3y+5)), so:
7(3y+5)
We multiply parentheses
21y+35
Back to the equation:
-(21y+35)
We get rid of parentheses
15y-21y-35-6=0
We add all the numbers together, and all the variables
-6y-41=0
We move all terms containing y to the left, all other terms to the right
-6y=41
y=41/-6
y=-6+5/6

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