(X+2)(x+3)+(x-3)(x-2x)(x+1)=0

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Solution for (X+2)(x+3)+(x-3)(x-2x)(x+1)=0 equation: 



(X+2)(X+3)+(X-3)(X-2X)(X+1)=0

We add all the numbers together, and all the variables

(X+2)(X+3)+(X-3)(-1X)(X+1)=0

We multiply parentheses ..

(+X^2+3X+2X+6)+(X-3)(-1X)(X+1)=0

We get rid of parentheses

X^2+3X+2X+(X-3)(-1X)(X+1)+6=0

We multiply parentheses ..

X^2+(-1X^2+3X)(X+1)+3X+2X+6=0

We add all the numbers together, and all the variables

X^2+(-1X^2+3X)(X+1)+5X+6=0

We move all terms containing X to the left, all other terms to the right

X^2+(-1X^2+3X)(X+1)+5X=-6

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