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x(4x+18)=166
We move all terms to the left:
x(4x+18)-(166)=0
We multiply parentheses
4x^2+18x-166=0
a = 4; b = 18; c = -166;
Δ = b2-4ac
Δ = 182-4·4·(-166)
Δ = 2980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2980}=\sqrt{4*745}=\sqrt{4}*\sqrt{745}=2\sqrt{745}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{745}}{2*4}=\frac{-18-2\sqrt{745}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{745}}{2*4}=\frac{-18+2\sqrt{745}}{8} $
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