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3(5x-5)-2(2x-10)=5(2x+4)-3
We move all terms to the left:
3(5x-5)-2(2x-10)-(5(2x+4)-3)=0
We multiply parentheses
15x-4x-(5(2x+4)-3)-15+20=0
We calculate terms in parentheses: -(5(2x+4)-3), so:We add all the numbers together, and all the variables
5(2x+4)-3
We multiply parentheses
10x+20-3
We add all the numbers together, and all the variables
10x+17
Back to the equation:
-(10x+17)
11x-(10x+17)+5=0
We get rid of parentheses
11x-10x-17+5=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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