3(2y+5)=-4(y+2)

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Solution for 3(2y+5)=-4(y+2) equation: 



3(2y+5)=-4(y+2)

We move all terms to the left:

3(2y+5)-(-4(y+2))=0

We multiply parentheses

6y-(-4(y+2))+15=0



We calculate terms in parentheses: -(-4(y+2)), so:

-4(y+2)

We multiply parentheses

-4y-8

Back to the equation:

-(-4y-8)



We get rid of parentheses

6y+4y+8+15=0

We add all the numbers together, and all the variables

10y+23=0

We move all terms containing y to the left, all other terms to the right

10y=-23

y=-23/10

y=-2+3/10

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