4(z+3)=14z+21

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Solution for 4(z+3)=14z+21 equation: 



4(z+3)=14z+21

We move all terms to the left:

4(z+3)-(14z+21)=0

We multiply parentheses

4z-(14z+21)+12=0

We get rid of parentheses

4z-14z-21+12=0

We add all the numbers together, and all the variables

-10z-9=0

We move all terms containing z to the left, all other terms to the right

-10z=9

z=9/-10

z=-9/10

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