3(4y-6)=8y-18+4y

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Solution for 3(4y-6)=8y-18+4y equation: 



3(4y-6)=8y-18+4y

We move all terms to the left:

3(4y-6)-(8y-18+4y)=0

We add all the numbers together, and all the variables

3(4y-6)-(12y-18)=0

We multiply parentheses

12y-(12y-18)-18=0

We get rid of parentheses

12y-12y+18-18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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