2x+3/(x+2)(x-2)-5/x-2=4/x+2

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Solution for 2x+3/(x+2)(x-2)-5/x-2=4/x+2 equation: 



2x+3/(x+2)(x-2)-5/x-2=4/x+2

We move all terms to the left:

2x+3/(x+2)(x-2)-5/x-2-(4/x+2)=0



Domain of the equation: (x+2)(x-2)!=0

We move all terms containing x to the left, all other terms to the right

x+2)(x!=2

x∈R





Domain of the equation: x!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We use the square of the difference formula

x^2+2x-5/x-(4/x+2)-4-2=0

We get rid of parentheses

x^2+2x-5/x-4/x-2-4-2=0

We multiply all the terms by the denominator


x^2*x+2x*x-2*x-4*x-2*x-5-4=0

We add all the numbers together, and all the variables

x^2*x-8x+2x*x-9=0

Wy multiply elements

x^3+2x^2-8x-9=0

We do not support expression: x^3

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