3(x-1)+4(x+2)=5(x-3)+4(x+3)

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Solution for 3(x-1)+4(x+2)=5(x-3)+4(x+3) equation: 



3(x-1)+4(x+2)=5(x-3)+4(x+3)

We move all terms to the left:

3(x-1)+4(x+2)-(5(x-3)+4(x+3))=0

We multiply parentheses

3x+4x-(5(x-3)+4(x+3))-3+8=0



We calculate terms in parentheses: -(5(x-3)+4(x+3)), so:

5(x-3)+4(x+3)

We multiply parentheses

5x+4x-15+12

We add all the numbers together, and all the variables

9x-3

Back to the equation:

-(9x-3)



We add all the numbers together, and all the variables

7x-(9x-3)+5=0

We get rid of parentheses

7x-9x+3+5=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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