3(4x-28)=3(20-2x)

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Solution for 3(4x-28)=3(20-2x) equation: 



3(4x-28)=3(20-2x)

We move all terms to the left:

3(4x-28)-(3(20-2x))=0

We add all the numbers together, and all the variables

3(4x-28)-(3(-2x+20))=0

We multiply parentheses

12x-(3(-2x+20))-84=0



We calculate terms in parentheses: -(3(-2x+20)), so:

3(-2x+20)

We multiply parentheses

-6x+60

Back to the equation:

-(-6x+60)



We get rid of parentheses

12x+6x-60-84=0

We add all the numbers together, and all the variables

18x-144=0

We move all terms containing x to the left, all other terms to the right

18x=144

x=144/18

x=8

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