(1/3(102-2x))+2x=102

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Solution for (1/3(102-2x))+2x=102 equation: 



(1/3(102-2x))+2x=102

We move all terms to the left:

(1/3(102-2x))+2x-(102)=0



Domain of the equation: 3(102-2x))!=0

x∈R



We add all the numbers together, and all the variables

(1/3(-2x+102))+2x-102=0

We add all the numbers together, and all the variables

2x+(1/3(-2x+102))-102=0

We multiply all the terms by the denominator


2x*3(-2x+102))+(1-102*3(-2x+102))=0

Wy multiply elements

6x^2(--306x(-=0

We use the square of the difference formula

6x^2(+306x(-=0

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