6(4k-1)=-6(1+6k)+8k

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Solution for 6(4k-1)=-6(1+6k)+8k equation: 



6(4k-1)=-6(1+6k)+8k

We move all terms to the left:

6(4k-1)-(-6(1+6k)+8k)=0

We add all the numbers together, and all the variables

6(4k-1)-(-6(6k+1)+8k)=0

We multiply parentheses

24k-(-6(6k+1)+8k)-6=0



We calculate terms in parentheses: -(-6(6k+1)+8k), so:

-6(6k+1)+8k

We add all the numbers together, and all the variables

8k-6(6k+1)

We multiply parentheses

8k-36k-6

We add all the numbers together, and all the variables

-28k-6

Back to the equation:

-(-28k-6)



We get rid of parentheses

24k+28k+6-6=0

We add all the numbers together, and all the variables

52k=0

k=0/52

k=0

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