3(4x+2)=-12(x-4)+6

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Solution for 3(4x+2)=-12(x-4)+6 equation: 



3(4x+2)=-12(x-4)+6

We move all terms to the left:

3(4x+2)-(-12(x-4)+6)=0

We multiply parentheses

12x-(-12(x-4)+6)+6=0



We calculate terms in parentheses: -(-12(x-4)+6), so:

-12(x-4)+6

We multiply parentheses

-12x+48+6

We add all the numbers together, and all the variables

-12x+54

Back to the equation:

-(-12x+54)



We get rid of parentheses

12x+12x-54+6=0

We add all the numbers together, and all the variables

24x-48=0

We move all terms containing x to the left, all other terms to the right

24x=48

x=48/24

x=2

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