20x2+20x+5=0

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Solution for 20x2+20x+5=0 equation:



20x^2+20x+5=0
a = 20; b = 20; c = +5;
Δ = b2-4ac
Δ = 202-4·20·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{40}=-1/2$

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