110=(4+x)(28-2x)

Solution for 110=(4+x)(28-2x) equation:

110=(4+x)(28-2x)

We move all terms to the left:

110-((4+x)(28-2x))=0

We add all the numbers together, and all the variables

-((x+4)(-2x+28))+110=0

We multiply parentheses ..

-((-2x^2+28x-8x+112))+110=0


We calculate terms in parentheses: -((-2x^2+28x-8x+112)), so:

(-2x^2+28x-8x+112)

We get rid of parentheses

-2x^2+28x-8x+112

We add all the numbers together, and all the variables

-2x^2+20x+112

Back to the equation:

-(-2x^2+20x+112)


We get rid of parentheses

2x^2-20x-112+110=0

We add all the numbers together, and all the variables

2x^2-20x-2=0

a = 2; b = -20; c = -2;
Δ = b2-4ac
Δ = -202-4·2·(-2)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{26}}{2*2}=\frac{20-4\sqrt{26}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{26}}{2*2}=\frac{20+4\sqrt{26}}{4}
$