3(4+4)+2r+40=2

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Solution for 3(4+4)+2r+40=2 equation: 



3(4+4)+2r+40=2

We move all terms to the left:

3(4+4)+2r+40-(2)=0

determiningTheFunctionDomain
2r+40-2+3(4+4)=0

We add all the numbers together, and all the variables

2r+40-2+38=0

We add all the numbers together, and all the variables

2r+76=0

We move all terms containing r to the left, all other terms to the right

2r=-76

r=-76/2

r=-38

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