3(4+2a)=5(3+4a)

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Solution for 3(4+2a)=5(3+4a) equation: 



3(4+2a)=5(3+4a)

We move all terms to the left:

3(4+2a)-(5(3+4a))=0

We add all the numbers together, and all the variables

3(2a+4)-(5(4a+3))=0

We multiply parentheses

6a-(5(4a+3))+12=0



We calculate terms in parentheses: -(5(4a+3)), so:

5(4a+3)

We multiply parentheses

20a+15

Back to the equation:

-(20a+15)



We get rid of parentheses

6a-20a-15+12=0

We add all the numbers together, and all the variables

-14a-3=0

We move all terms containing a to the left, all other terms to the right

-14a=3

a=3/-14

a=-3/14

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