3(7y-13)=5(3-y)-y

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Solution for 3(7y-13)=5(3-y)-y equation: 



3(7y-13)=5(3-y)-y

We move all terms to the left:

3(7y-13)-(5(3-y)-y)=0

We add all the numbers together, and all the variables

3(7y-13)-(5(-1y+3)-y)=0

We multiply parentheses

21y-(5(-1y+3)-y)-39=0



We calculate terms in parentheses: -(5(-1y+3)-y), so:

5(-1y+3)-y

We add all the numbers together, and all the variables

-1y+5(-1y+3)

We multiply parentheses

-1y-5y+15

We add all the numbers together, and all the variables

-6y+15

Back to the equation:

-(-6y+15)



We get rid of parentheses

21y+6y-15-39=0

We add all the numbers together, and all the variables

27y-54=0

We move all terms containing y to the left, all other terms to the right

27y=54

y=54/27

y=2

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