3(3y-7)+4=6y-5

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Solution for 3(3y-7)+4=6y-5 equation: 



3(3y-7)+4=6y-5

We move all terms to the left:

3(3y-7)+4-(6y-5)=0

We multiply parentheses

9y-(6y-5)-21+4=0

We get rid of parentheses

9y-6y+5-21+4=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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