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2/5x-18/2=-4x
We move all terms to the left:
2/5x-18/2-(-4x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-(-4x)-9=0
We get rid of parentheses
2/5x+4x-9=0
We multiply all the terms by the denominator
4x*5x-9*5x+2=0
Wy multiply elements
20x^2-45x+2=0
a = 20; b = -45; c = +2;
Δ = b2-4ac
Δ = -452-4·20·2
Δ = 1865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1865}}{2*20}=\frac{45-\sqrt{1865}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1865}}{2*20}=\frac{45+\sqrt{1865}}{40} $
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