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2(x+6)=2(6+(1/3)x)
We move all terms to the left:
2(x+6)-(2(6+(1/3)x))=0
Domain of the equation: 3)x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(x+6)-(2(6+(+1/3)x))=0
We multiply parentheses
2x-(2(6+(+1/3)x))+12=0
We multiply all the terms by the denominator
2x*3)x))-(2(6+(+12*3)x))+1=0
We add all the numbers together, and all the variables
2x*3)x))-(2(6+36x))+1=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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