2/5b-8=-1.5b+7

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Solution for 2/5b-8=-1.5b+7 equation:



2/5b-8=-1.5b+7
We move all terms to the left:
2/5b-8-(-1.5b+7)=0
Domain of the equation: 5b!=0
b!=0/5
b!=0
b∈R
We get rid of parentheses
2/5b+1.5b-7-8=0
We multiply all the terms by the denominator
(1.5b)*5b-7*5b-8*5b+2=0
We add all the numbers together, and all the variables
(+1.5b)*5b-7*5b-8*5b+2=0
We multiply parentheses
5b^2-7*5b-8*5b+2=0
Wy multiply elements
5b^2-35b-40b+2=0
We add all the numbers together, and all the variables
5b^2-75b+2=0
a = 5; b = -75; c = +2;
Δ = b2-4ac
Δ = -752-4·5·2
Δ = 5585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5585}}{2*5}=\frac{75-\sqrt{5585}}{10} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5585}}{2*5}=\frac{75+\sqrt{5585}}{10} $

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