3(3y-5)=4(5y-1)

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Solution for 3(3y-5)=4(5y-1) equation: 



3(3y-5)=4(5y-1)

We move all terms to the left:

3(3y-5)-(4(5y-1))=0

We multiply parentheses

9y-(4(5y-1))-15=0



We calculate terms in parentheses: -(4(5y-1)), so:

4(5y-1)

We multiply parentheses

20y-4

Back to the equation:

-(20y-4)



We get rid of parentheses

9y-20y+4-15=0

We add all the numbers together, and all the variables

-11y-11=0

We move all terms containing y to the left, all other terms to the right

-11y=11

y=11/-11

y=-1

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