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2x+12=2x(x+6)
We move all terms to the left:
2x+12-(2x(x+6))=0
We calculate terms in parentheses: -(2x(x+6)), so:We get rid of parentheses
2x(x+6)
We multiply parentheses
2x^2+12x
Back to the equation:
-(2x^2+12x)
-2x^2+2x-12x+12=0
We add all the numbers together, and all the variables
-2x^2-10x+12=0
a = -2; b = -10; c = +12;
Δ = b2-4ac
Δ = -102-4·(-2)·12
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*-2}=\frac{-4}{-4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*-2}=\frac{24}{-4} =-6 $
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