3(3y-1)3(2y)=22

Solution for 3(3y-1)3(2y)=22 equation:

3(3y-1)3(2y)=22

We move all terms to the left:

3(3y-1)3(2y)-(22)=0

We multiply parentheses

288y^2-96y-22=0

a = 288; b = -96; c = -22;
Δ = b2-4ac
Δ = -962-4·288·(-22)
Δ = 34560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34560}=\sqrt{2304*15}=\sqrt{2304}*\sqrt{15}=48\sqrt{15}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-48\sqrt{15}}{2*288}=\frac{96-48\sqrt{15}}{576}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+48\sqrt{15}}{2*288}=\frac{96+48\sqrt{15}}{576}
$