7y+4(y+6)=3(y+2)-3

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Solution for 7y+4(y+6)=3(y+2)-3 equation: 



7y+4(y+6)=3(y+2)-3

We move all terms to the left:

7y+4(y+6)-(3(y+2)-3)=0

We multiply parentheses

7y+4y-(3(y+2)-3)+24=0



We calculate terms in parentheses: -(3(y+2)-3), so:

3(y+2)-3

We multiply parentheses

3y+6-3

We add all the numbers together, and all the variables

3y+3

Back to the equation:

-(3y+3)



We add all the numbers together, and all the variables

11y-(3y+3)+24=0

We get rid of parentheses

11y-3y-3+24=0

We add all the numbers together, and all the variables

8y+21=0

We move all terms containing y to the left, all other terms to the right

8y=-21

y=-21/8

y=-2+5/8

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