2x(x+4)+1=-1

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Solution for 2x(x+4)+1=-1 equation:



2x(x+4)+1=-1
We move all terms to the left:
2x(x+4)+1-(-1)=0
We add all the numbers together, and all the variables
2x(x+4)+2=0
We multiply parentheses
2x^2+8x+2=0
a = 2; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·2·2
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{3}}{2*2}=\frac{-8-4\sqrt{3}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{3}}{2*2}=\frac{-8+4\sqrt{3}}{4} $

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