3(3y+3)-y=1

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Solution for 3(3y+3)-y=1 equation: 



3(3y+3)-y=1

We move all terms to the left:

3(3y+3)-y-(1)=0

We add all the numbers together, and all the variables

-1y+3(3y+3)-1=0

We multiply parentheses

-1y+9y+9-1=0

We add all the numbers together, and all the variables

8y+8=0

We move all terms containing y to the left, all other terms to the right

8y=-8

y=-8/8

y=-1

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