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=5/9C(9-32)
We move all terms to the left:
-(5/9C(9-32))=0
Domain of the equation: 9C(9-32))!=0We add all the numbers together, and all the variables
C∈R
-(5/9C(-23))=0
We multiply all the terms by the denominator
-(5=0
We add all the numbers together, and all the variables
=0
C=0/1
C=0