3(3y+1)=2(2y+15)

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Solution for 3(3y+1)=2(2y+15) equation: 



3(3y+1)=2(2y+15)

We move all terms to the left:

3(3y+1)-(2(2y+15))=0

We multiply parentheses

9y-(2(2y+15))+3=0



We calculate terms in parentheses: -(2(2y+15)), so:

2(2y+15)

We multiply parentheses

4y+30

Back to the equation:

-(4y+30)



We get rid of parentheses

9y-4y-30+3=0

We add all the numbers together, and all the variables

5y-27=0

We move all terms containing y to the left, all other terms to the right

5y=27

y=27/5

y=5+2/5

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