3(3x-2)=6x+12

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Solution for 3(3x-2)=6x+12 equation: 



3(3x-2)=6x+12

We move all terms to the left:

3(3x-2)-(6x+12)=0

We multiply parentheses

9x-(6x+12)-6=0

We get rid of parentheses

9x-6x-12-6=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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