6x+3(3-2x)=12(2-x)

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Solution for 6x+3(3-2x)=12(2-x) equation: 



6x+3(3-2x)=12(2-x)

We move all terms to the left:

6x+3(3-2x)-(12(2-x))=0

We add all the numbers together, and all the variables

6x+3(-2x+3)-(12(-1x+2))=0

We multiply parentheses

6x-6x-(12(-1x+2))+9=0



We calculate terms in parentheses: -(12(-1x+2)), so:

12(-1x+2)

We multiply parentheses

-12x+24

Back to the equation:

-(-12x+24)



We add all the numbers together, and all the variables

-(-12x+24)+9=0

We get rid of parentheses

12x-24+9=0

We add all the numbers together, and all the variables

12x-15=0

We move all terms containing x to the left, all other terms to the right

12x=15

x=15/12

x=1+1/4

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