(2y-5)/6=-12

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Solution for (2y-5)/6=-12 equation: 



(2y-5)/6=-12

We move all terms to the left:

(2y-5)/6-(-12)=0

We add all the numbers together, and all the variables

(2y-5)/6+12=0

We multiply all the terms by the denominator


(2y-5)+12*6=0

We add all the numbers together, and all the variables

(2y-5)+72=0

We get rid of parentheses

2y-5+72=0

We add all the numbers together, and all the variables

2y+67=0

We move all terms containing y to the left, all other terms to the right

2y=-67

y=-67/2

y=-33+1/2

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