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3(3x+4)+3(4x+4)+3=21x+27
We move all terms to the left:
3(3x+4)+3(4x+4)+3-(21x+27)=0
We multiply parentheses
9x+12x-(21x+27)+12+12+3=0
We get rid of parentheses
9x+12x-21x-27+12+12+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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