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7x-3x(x-1)=2(2x+3)
We move all terms to the left:
7x-3x(x-1)-(2(2x+3))=0
We multiply parentheses
-3x^2+7x+3x-(2(2x+3))=0
We calculate terms in parentheses: -(2(2x+3)), so:We add all the numbers together, and all the variables
2(2x+3)
We multiply parentheses
4x+6
Back to the equation:
-(4x+6)
-3x^2+10x-(4x+6)=0
We get rid of parentheses
-3x^2+10x-4x-6=0
We add all the numbers together, and all the variables
-3x^2+6x-6=0
a = -3; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·(-3)·(-6)
Δ = -36
Delta is less than zero, so there is no solution for the equation
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