3(x+4)+19=16-4x

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Solution for 3(x+4)+19=16-4x equation: 



3(x+4)+19=16-4x

We move all terms to the left:

3(x+4)+19-(16-4x)=0

We add all the numbers together, and all the variables

3(x+4)-(-4x+16)+19=0

We multiply parentheses

3x-(-4x+16)+12+19=0

We get rid of parentheses

3x+4x-16+12+19=0

We add all the numbers together, and all the variables

7x+15=0

We move all terms containing x to the left, all other terms to the right

7x=-15

x=-15/7

x=-2+1/7

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