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3(3n-5)=(6n+1)+3
We move all terms to the left:
3(3n-5)-((6n+1)+3)=0
We multiply parentheses
9n-((6n+1)+3)-15=0
We calculate terms in parentheses: -((6n+1)+3), so:We get rid of parentheses
(6n+1)+3
We get rid of parentheses
6n+1+3
We add all the numbers together, and all the variables
6n+4
Back to the equation:
-(6n+4)
9n-6n-4-15=0
We add all the numbers together, and all the variables
3n-19=0
We move all terms containing n to the left, all other terms to the right
3n=19
n=19/3
n=6+1/3
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