2(y-3)=6(2y+3)

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Solution for 2(y-3)=6(2y+3) equation: 



2(y-3)=6(2y+3)

We move all terms to the left:

2(y-3)-(6(2y+3))=0

We multiply parentheses

2y-(6(2y+3))-6=0



We calculate terms in parentheses: -(6(2y+3)), so:

6(2y+3)

We multiply parentheses

12y+18

Back to the equation:

-(12y+18)



We get rid of parentheses

2y-12y-18-6=0

We add all the numbers together, and all the variables

-10y-24=0

We move all terms containing y to the left, all other terms to the right

-10y=24

y=24/-10

y=-2+2/5

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