5y+2(y-6)=3(y-1)-2

Solution for 5y+2(y-6)=3(y-1)-2 equation:

5y+2(y-6)=3(y-1)-2

We move all terms to the left:

5y+2(y-6)-(3(y-1)-2)=0

We multiply parentheses

5y+2y-(3(y-1)-2)-12=0


We calculate terms in parentheses: -(3(y-1)-2), so:

3(y-1)-2

We multiply parentheses

3y-3-2

We add all the numbers together, and all the variables

3y-5

Back to the equation:

-(3y-5)


We add all the numbers together, and all the variables

7y-(3y-5)-12=0

We get rid of parentheses

7y-3y+5-12=0

We add all the numbers together, and all the variables

4y-7=0

We move all terms containing y to the left, all other terms to the right

4y=7

y=7/4

y=1+3/4