3(3a+5)-5a=40-a

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Solution for 3(3a+5)-5a=40-a equation: 



3(3a+5)-5a=40-a

We move all terms to the left:

3(3a+5)-5a-(40-a)=0

We add all the numbers together, and all the variables

3(3a+5)-5a-(-1a+40)=0

We add all the numbers together, and all the variables

-5a+3(3a+5)-(-1a+40)=0

We multiply parentheses

-5a+9a-(-1a+40)+15=0

We get rid of parentheses

-5a+9a+1a-40+15=0

We add all the numbers together, and all the variables

5a-25=0

We move all terms containing a to the left, all other terms to the right

5a=25

a=25/5

a=5

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