3(2z-6)-4(3Z+1)=5-Z(Z+1)

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Solution for 3(2z-6)-4(3Z+1)=5-Z(Z+1) equation: 



3(2z-6)-4(3+1)=5-(+1)

We move all terms to the left:

3(2z-6)-4(3+1)-(5-(+1))=0

We add all the numbers together, and all the variables

3(2z-6)-44-(5-1)=0

We add all the numbers together, and all the variables

3(2z-6)-48=0

We multiply parentheses

6z-18-48=0

We add all the numbers together, and all the variables

6z-66=0

We move all terms containing z to the left, all other terms to the right

6z=66

z=66/6

z=11

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