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t=t2+1.3333333333t+0.25
We move all terms to the left:
t-(t2+1.3333333333t+0.25)=0
We add all the numbers together, and all the variables
-(+t^2+1.3333333333t+0.25)+t=0
We get rid of parentheses
-t^2-1.3333333333t+t-0.25=0
We add all the numbers together, and all the variables
-1t^2-0.3333333333t-0.25=0
a = -1; b = -0.3333333333; c = -0.25;
Δ = b2-4ac
Δ = -0.33333333332-4·(-1)·(-0.25)
Δ = -0.88888888891111
Delta is less than zero, so there is no solution for the equation
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