10+5(4x+3)=19x+20

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Solution for 10+5(4x+3)=19x+20 equation: 



10+5(4x+3)=19x+20

We move all terms to the left:

10+5(4x+3)-(19x+20)=0

We multiply parentheses

20x-(19x+20)+15+10=0

We get rid of parentheses

20x-19x-20+15+10=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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