3(2z-30)=2(2z+5)

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Solution for 3(2z-30)=2(2z+5) equation: 



3(2z-30)=2(2z+5)

We move all terms to the left:

3(2z-30)-(2(2z+5))=0

We multiply parentheses

6z-(2(2z+5))-90=0



We calculate terms in parentheses: -(2(2z+5)), so:

2(2z+5)

We multiply parentheses

4z+10

Back to the equation:

-(4z+10)



We get rid of parentheses

6z-4z-10-90=0

We add all the numbers together, and all the variables

2z-100=0

We move all terms containing z to the left, all other terms to the right

2z=100

z=100/2

z=50

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