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3(2y-4)=2(3y-6)
We move all terms to the left:
3(2y-4)-(2(3y-6))=0
We multiply parentheses
6y-(2(3y-6))-12=0
We calculate terms in parentheses: -(2(3y-6)), so:We get rid of parentheses
2(3y-6)
We multiply parentheses
6y-12
Back to the equation:
-(6y-12)
6y-6y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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