1/x-2+2x/(x-2)(x-8)=x/2(x-8)

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Solution for 1/x-2+2x/(x-2)(x-8)=x/2(x-8) equation: 



1/x-2+2x/(x-2)(x-8)=x/2(x-8)

We move all terms to the left:

1/x-2+2x/(x-2)(x-8)-(x/2(x-8))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-2)(x-8)!=0

We move all terms containing x to the left, all other terms to the right

x-2)(x!=8

x∈R





Domain of the equation: 2(x-8))!=0

x∈R



We multiply parentheses ..

2x/(+x^2-8x-2x+16)+1/x-(x/2(x-8))-2=0

We calculate fractions

We do not support expression: x^3

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