3n+2(4n-5)=n-30

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Solution for 3n+2(4n-5)=n-30 equation: 



3n+2(4n-5)=n-30

We move all terms to the left:

3n+2(4n-5)-(n-30)=0

We multiply parentheses

3n+8n-(n-30)-10=0

We get rid of parentheses

3n+8n-n+30-10=0

We add all the numbers together, and all the variables

10n+20=0

We move all terms containing n to the left, all other terms to the right

10n=-20

n=-20/10

n=-2

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