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3(2x-5)=2(x+10)-15
We move all terms to the left:
3(2x-5)-(2(x+10)-15)=0
We multiply parentheses
6x-(2(x+10)-15)-15=0
We calculate terms in parentheses: -(2(x+10)-15), so:We get rid of parentheses
2(x+10)-15
We multiply parentheses
2x+20-15
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
6x-2x-5-15=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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